Example code:
int a = 255; byte b = (byte) a; int c = b & 0xff; // Here be dragons System.out.println(a); System.out.println(b); System.out.println(c);
So we start with an integer value of 255, convert it to a byte (becoming -1) and then converting it back to an int by using a magic formula. The expected output is:
255 -1 255
I'm wondering if this a & 0xff
is the most elegant way to to this conversion. checkstyle for example complains about using a magic number at this place and it's not a good idea to ignore this value for this check because in other places 255 may really be a magic number which should be avoided. And it's quite annoying to define a constant for stuff like this on my own. So I wonder if there is a standard method in JRE which does this conversion instead? Or maybe an already defined constant with the highest unsigned byte value (similar to Byte.MAX_VALUE which is the highest signed value)
So to keep the question short: How can I convert a byte to an int without using a magic number?
Ok, so far the following possibilities were mentioned:
& 0xff
and ignore the magic number 255 in checkstyle. Disadvantage: Other places which may use this number in some other scope (not bit operations) are not checked then, too. Advantage: Short and easy to read.& SomeConsts.MAX_UNSIGNED_BYTE_VALUE
. Disadvantage: If I need it in different classes then I have to define my own constant class just for this darn constant. Advantage: No magic numbers here.b & ((1 << Byte.SIZE) - 1)
. The compiler output is most likely the same because it gets optimized to a constant value. Disadvantage: Pretty much code, difficult to read. Advantage: As long as 1
is not defined as magic number (checkstyle ignores it by default) we have no magic number here and we don't need to define custom constants. And when bytes are redefined to be 16 bit some day (Just kidding) then it still works because then Byte.SIZE will be 16 and not 8.Are there more ideas? Maybe some other clever bit-wise operation which is shorter then the one above and only uses numbers like 0 and 1?
The intValue() method of Byte class is a built in method in Java which is used to return the value of this Byte object as int.
Method 2: Using BigInteger The BigInteger class has a longValue() method to convert a byte array to a long value: long value = new BigInteger(bytes). longValue(); Java.
We can directly assign the byte to the int data type. Secondly, we have a Wrapper class method intValue() that returns the value of byte as an int after widening the primitive conversion as we're storing a smaller data type into a larger one. If we take the byte as unsigned, then we have the Byte.
This is the standard way to do that transformation. If you want to get rid of the checkstyle complaints, try defining a constant, it could help:
public final static int MASK = 0xff;
BTW - keep in mind, that it is still a custom conversion. byte
is a signed datatype so a byte
can never hold the value 255
. A byte can store the bit pattern 1111 1111
but this represents the integer value -1
.
So in fact you're doing bit operations - and bit operations always require some magic numbers.
BTW-2 : Yes, there is a Byte.MAX_VALUE
constant but this is - because byte
is signed - defined as 27-1 (= 127). So it won't help in your case. You need a byte constant for -1.
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