Most efficient way to remove leading zeros from Swift 3 string

Question

I have a string such as "00123456" that I would like to have in an string "123456", with the leading zeros removed.

I've found several examples for Objective-C but not sure best way to do so with Swift 3.

Thanks

Answer 1

You can do that with Regular Expression

let string = "00123456"
let trimmedString = string.replacingOccurrences(of: "^0+", with: "", options: .regularExpression)

The benefit is no double conversion and no force unwrapping.

Answer 2

Just convert the string to an int and then back to a string again. It will remove the leading zeros.

let numberString = "00123456"
let numberAsInt = Int(numberString)
let backToString = "\(numberAsInt!)"

Result: "123456"