Most concise way to create a python dictionary from local variables

Question

In Objective-C, you can use the NSDictionaryOfVariableBindings macro to create a dictionary like this

NSString *foo = @"bar"
NSString *flip = @"rar"
NSDictionary *d = NSDictionaryOfVariableBindings(foo, flip)
// d -> { 'foo' => 'bar', 'flip' => 'rar' }

Is there something similar in python? I often find myself writing code like this

d = {'foo': foo, 'flip': flip}
# or
d = dict(foo=foo, flip=flip)

Is there a shortcut to do something like this?

d = dict(foo, flip) # -> {'foo': 'bar', 'flip': 'rar'}

Answer 1

No, this shortcut in python does not exist.

But perhaps this is what you need:

>>> def test():
...     x = 42
...     y = 43
...     return locals()
>>> test()
{'y': 43, 'x': 42}

Also, python provides globals() and vars() build-in functions for such things. See the doc.

Answer 2

have you tried vars()

vars([object])
Return the __dict__ attribute for a module, class, instance, or any other object with a __dict__ attribute.

Objects such as modules and instances have an updateable __dict__ attribute; however, other objects may have write restrictions on their __dict__ attributes (for example, new-style classes use a dictproxy to prevent direct dictionary updates).

so

variables = vars()
dictionary_of_bindings = {x:variables[x] for x in ("foo", "flip")}