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Anyone knows of a more concise/elegant way of achieving the following?
A = B if B?
Thanks.
I'm looking for a solution that references A and B once only. And would compile toif (typeof B !== "undefined" && B !== null) { A = B; }
or something else similar.
To have this short helps have the following a bit more readable:someObject[someAttribute] = (someOtherObject[someOtherAttribute] if someOtherObject[someOtherAttribute]?)
That is the motivation for my question.
943
In JavaScript, before using a variable, we need to declare and initialize it (assign value). Unlike JavaScript, while creating a variable in CoffeeScript, there is no need to declare it using the var keyword. We simply create a variable just by assigning a value to a literal as shown below.
Automatically Global If you assign a value to a variable that has not been declared, it will automatically become a GLOBAL variable. This code example will declare a global variable carName , even if the value is assigned inside a function.
If you assign a value to a variable that you have not declared with var , JavaScript implicitly declares that variable for you. Note, however, that implicitly declared variables are always created as global variables, even if they are used within the body of a function.
if (typeof MyVariable !== "undefined" && MyVariable !==
You could say:
a = b ? a
For example, this:
a = 11
a = b ? a
console.log(a)
b = 23
a = b ? a
console.log(a)
will give you 11 and 23 in the console (demo: http://jsfiddle.net/ambiguous/ngtEE/)
123
Maybe something like:
A=_ if (_=B)?
expanded:
if ((_ = B) != null) {
A = _;
}
This will overwrite A with what ever is in B, but only if it is not null, referencing both only once.
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