I have a collection structured thusly:
{
_id: 1,
score: [
{
foo: 'a',
bar: 0,
user: {user1: 0, user2: 7}
}
]
}
I need to find all documents that have at least one 'score' (element in score array) that has a certain value of 'bar' and a non-empty 'user' sub-document.
This is what I came up with (and it seemed like it should work):
db.col.find({score: {"$elemMatch": {bar:0, user: {"$not":{}} }}})
But, I get this error:
error: { "$err" : "$not cannot be empty", "code" : 13030 }
Any other way to do this?
Figured it out: { 'score.user': { "$gt": {} } }
will match non-empty docs.
I'm not sure I quite understand your schema, but perhaps the most straight forward way would be to not have an "empty" value for score.user ?
Instead purposely not have that field in your document if it has no content?
Then your query could be something like ...
> db.test.find({ "score" : { "$elemMatch" : { bar : 0, "user" : {"$exists": true }}}})
i.e. looking for a value in score.bar that you want (0 in this case) checking for the mear existence ($exists, see docs) of score.user (and if it has a value, then it'll exist?)
editied: oops I missed the $elemMatch you had ...
You probably want to add an auxiliary array that keeps track of the users in the user
document:
{
_id: 1,
score: [
{
foo: 'a',
bar: 0,
users: ["user1", "user2"],
user: {user1: 0, user2: 7}
}
]
}
Then you can add new users atomically:
> db.test.update({_id: 1, score: { $elemMatch: {bar: 0}}},
... {$set: {'score.$.user.user3': 10}, $addToSet: {'score.$.users': "user3"}})
Remove users:
> db.test.update({_id: 1, score: { $elemMatch: {bar: 0}}},
... {$unset: {'score.$.user.user3': 1}, $pop: {'score.$.users': "user3"}})
Query scores:
> db.test.find({_id: 1, score: {$elemMatch: {bar: 0, users: {$not: {$size: 0}}}}})
If you know you'll only be adding non-existent users and removing existent users from the user
document, you can simplify users
to a counter instead of an array, but the above is more resilient.
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