I'm trying to perform an aggregation operation using in Java using the mongo-java-driver. I've performed some other find operations, but I'm unable to do the following aggregation correctly in Java:
db.I1.aggregate([
{ "$match": { "ci": 862222} },
{ "$match": { "gi": { "$ne": null } }},
{ "$group": {
"_id": {
"ci": "$ci",
"gi": "$gi",
"gn": "$gn",
"si": "$si"
}
}},
{ "$group": {
"_id": {
"ci": "$_id.ci",
"gi": "$_id.gi",
"gn": "$_id.gn"
},
"sn": { "$sum": 1 }
}},
{ "$sort" : { "_id.gi" : 1}}
])
I've tried several ways and methods to perform that aggregation in Java, but I'm unable to include the group fields "ci", "gi", "gn","si"
correctly in the coll.aggregate(asList())
method. What I got so far, is the following:
MongoCollection<Document> coll = mongo.getCollection("I1");
Document matchCourse = new Document("$match",
new Document("ci", Integer.parseInt(courseid)));
Document matchGroupNotNull = new Document("$match",
new Document("gi", new Document("$ne", null)));
List<Object> list1 = new BasicDBList();
list1.add(new BasicDBObject("ci", "$ci"));
list1.add(new BasicDBObject("gi", "$gi"));
list1.add(new BasicDBObject("gn", "$gn"));
list1.add(new BasicDBObject("si", "$si"));
Document group1 = new Document(
"_id", list1).append("count", new Document("$sum", 1));
List<Object> list2 = new BasicDBList();
list2.add(new BasicDBObject("ci", "$_id.ci"));
list2.add(new BasicDBObject("gi", "$_id.gi"));
list2.add(new BasicDBObject("gn", "$_id.gn"));
Document group2 = new Document(
"_id", list2).append("sn", new Document("$sum", 1));
Document sort = new Document("$sort",
new Document("_id.gi", 1));
AggregateIterable<Document> iterable = coll.aggregate(asList(matchCourse,
matchGroupNotNull, group1, group2, sort));
I know it's not correct, but I included it to give you an idea of what I am doing. I've googled this in many different ways and read several pages, but I didn't find any solution. The available documentation for MongoDB-Java(1, 2) is too short for me and doesn't include this case.
How can I perform that query in Java? Any help would be appreciated.
Thank you very much!!
Finally I've come to a solution. There were some errors in the question that I posted, as it was the last attempt after reaching some point of desperation, but finally, here is the final solution:
MongoDatabase mongo = // initialize your connection;
Document matches = new Document("$match",
new Document("gi", new Document("$ne", null))
.append("ci", Integer.parseInt(courseid)));
Document firstGroup = new Document("$group",
new Document("_id",
new Document("ci", "$ci")
.append("gi", "$gi")
.append("gn", "$gn")
.append("si", "$si"))
.append("count", new Document("$sum", 1)));
Document secondGroup = new Document("$group",
new Document("_id",
new Document("ci", "$_id.ci")
.append("gi", "$_id.gi")
.append("gn", "$_id.gn"))
.append("ns", new Document("$sum", 1)));
Document sort = new Document("$sort",
new Document("_id.gi", 1));
List<Document> pipeline = Arrays.asList(matches, firstGroup,
secondGroup, sort);
AggregateIterable<Document> cursor = mongo.getCollection("I1")
.aggregate(pipeline);
for(Document doc : cursor) { // do stuff with doc }
Instead of trying to create lists of key-values, I just appended the elements to the documents. Hope it will be useful for somebody!!
This question is quite old but was the top match on google when I searched so if anyone is looking for a solution to this I managed to do it in the following way
Aggregation.group(Fields.fields()
.and("field1")
.and("field2"))
.first("name")
.`as`("name")
.count().`as`("count")
This will produce the following MDB query:
{ "$group" :
{ "_id" :
{ "field1" : "$field1", "field2" : "$field2"},
"name" : { "$first" : "$name"},
"count" : { "$sum" : 1}
}
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With