I'm currently checking whether an entry in a loop is the third iteration or not, with the following code:
<?php for ($i = 0; $i < count($category_news); $i++) : ?>
<div class="grid_8">
<div class="candidate snippet <?php if ($i % 3 == 2) echo "end"; ?>">
<div class="image shadow_50">
<img src="<?php echo base_url();?>media/uploads/news/<?php echo $category_news[$i]['url']; ?>" alt="Image Preview" width="70px" height="70px"/>
</div>
<h5><?php echo $category_news[$i]['title']?></h5>
<p><?php echo strip_tags(word_limiter($category_news[$i]['article'], 15)); ?></p>
<?php echo anchor('/news/article/id/'.$category_news[$i]['news_id'], '>>', array('class' => 'forward')); ?>
</div>
</div>
<?php if ($i % 3 == 2) : ?>
</li><li class="row">
<?php endif; ?>
<?php endfor; ?>
How can I check if the loop is in its second and not its third iteration?
I have tried $i % 2 == 1
to no avail.
The fmod() function returns the remainder (modulo) of x/y.
The modulus operator returns the remainder of a division of one number by another. In most programming languages, modulo is indicated with a percent sign. For example, "4 mod 2" or "4%2" returns 0, because 2 divides into 4 perfectly, without a remainder.
The typical usage of mod is for generating values inside a fixed range. In this case, you want values that are between 0 and strlen("abc")-1 so that you don't access a position outside "abc" . The general concept you need to keep in mind is that x % N will always return a value between 0 and N-1 .
Often when you write code, you want the same block of code to run over and over again a certain number of times. So, instead of adding several almost equal code-lines in a script, we can use loops. Loops are used to execute the same block of code again and again, as long as a certain condition is true.
Modulus checks what's the leftover of a division.
If $i is 10, 10/2 = 5 with no leftover, so $i modulus 2 would be 0.
If $i is 10, 10/3 = 3 with a leftover of 1, so $i modulus 3 would be 1.
To make it easier for you to track the number of item i would start $i from 1 instead of 0. e.g.
for($i=1; $i <= $count; $i++)
if($i % 2 == 0) echo 'This number is even as it is divisible by 2 with no leftovers! Horray!';
When in doubt, write a snippet of code:
for ($j = 1; $j < 4; $j++)
{
for ($k = 0; $k < $j; $k++)
{
echo "\n\$i % $j == $k: \n";
for ($i = 0; $i < 10; $i++)
{
echo "$i : ";
if ($i % $j == $k)
{
echo "TRUE";
}
echo " \n";
}
}
}
Here is the output. Use it to figure out what you need to use:
$i % 1 == 0:
0 : TRUE
1 : TRUE
2 : TRUE
3 : TRUE
4 : TRUE
5 : TRUE
6 : TRUE
7 : TRUE
8 : TRUE
9 : TRUE
$i % 2 == 0:
0 : TRUE
1 :
2 : TRUE
3 :
4 : TRUE
5 :
6 : TRUE
7 :
8 : TRUE
9 :
$i % 2 == 1:
0 :
1 : TRUE
2 :
3 : TRUE
4 :
5 : TRUE
6 :
7 : TRUE
8 :
9 : TRUE
$i % 3 == 0:
0 : TRUE
1 :
2 :
3 : TRUE
4 :
5 :
6 : TRUE
7 :
8 :
9 : TRUE
$i % 3 == 1:
0 :
1 : TRUE
2 :
3 :
4 : TRUE
5 :
6 :
7 : TRUE
8 :
9 :
$i % 3 == 2:
0 :
1 :
2 : TRUE
3 :
4 :
5 : TRUE
6 :
7 :
8 : TRUE
9 :
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