I am looking for a solution to a problem:
I have the NSAP address which is 20 characters long:
39250F800000000000000100011921680030081D
I now have to replace the last two characters of this string with F0
and the final string should look like:
39250F80000000000000010001192168003008F0
My current implementation chops the last two characters and appends F0
to it:
my $nsap = "39250F800000000000000100011921680030081D";
chop($nsap);
chop($nsap);
$nsap = $nsap."F0";
Is there a better way to accomplish this?
You can use substr
:
substr ($nsap, -2) = "F0";
or
substr ($nsap, -2, 2, "F0");
Or you can use a simple regex:
$nsap =~ s/..$/F0/;
This is from substr
's manpage:
substr EXPR,OFFSET,LENGTH,REPLACEMENT
substr EXPR,OFFSET,LENGTH
substr EXPR,OFFSET
Extracts a substring out of EXPR and returns it.
First character is at offset 0, or whatever you've
set $[ to (but don't do that). If OFFSET is nega-
tive (or more precisely, less than $[), starts
that far from the end of the string. If LENGTH is
omitted, returns everything to the end of the
string. If LENGTH is negative, leaves that many
characters off the end of the string.
Now, the interesting part is that the result of substr
can be used as an lvalue, and be assigned:
You can use the substr() function as an lvalue, in
which case EXPR must itself be an lvalue. If you
assign something shorter than LENGTH, the string
will shrink, and if you assign something longer
than LENGTH, the string will grow to accommodate
it. To keep the string the same length you may
need to pad or chop your value using "sprintf".
or you can use the replacement field:
An alternative to using substr() as an lvalue is
to specify the replacement string as the 4th argu-
ment. This allows you to replace parts of the
EXPR and return what was there before in one oper-
ation, just as you can with splice().
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