Method parameters order in Java [duplicate]

Question

Possible Duplicate:
Order of execution of parameters guarantees in Java?

If I have a Java method like:

    public void func(byte b, byte c) {...}

And I use it like this:

    a = 0;
    func(a++, a);

Wich parameter is passed first? Because if i'm not wrong, if it's the left one then b = 0 and c = 1. And if it's the right one then b = 0 and c = 0?

Thank you.

Answer 1

The arguments are evaluated left to right, as specified in the JLS - section 15.7.4.