I have a large (multi-GB) array in Matlab, that I want to truncate¹. Naively, I thought that truncating can't need much memory, but then I realised that it probably can:
>> Z = zeros(628000000, 1, 'single');
>> Z(364000000:end) = [];
Out of memory. Type HELP MEMORY for your options.
Unless Matlab does some clever optimisations, before truncating Z
, this code actually creates an array (of type double!) 364000000:628000000
. I don't need this array, so I can do instead:
>> Z = Z(1:363999999);
In this case, the second example works, and is fine for my purpose. But why does it work? If Z(364000000:end) = 0
fails due to the memory needed for the intermediate array 364000000:628000000
, then why does not Z = Z(1:363999999)
fail due to the memory needed for the intermediate array 1:363999999
, that is larger? Of course, I don't need this intermediate array, and would be happy with either a solution that truncates my array without having any intermediate array, or, failing that, if Matlab optimises a particular method.
¹Reason: I'm processing data but don't know how much to preallocate. I make an educated guess, often I'm allocating too much. I choose chunk size based on available memory, because splitting in fewer chunks means faster code. So I want to avoid any needless memory usage. See also this post on allocating by chunk.
I ran both examples on a machine with 24GB of RAM with profile('-memory','on');
. This profiler option will show memory allocated and freed on each line of code. These are supposed to be gross not net amounts. I checked with a simple function that has net 0 free and alloc and it reported the gross amounts. However, it seems likely that builtin commands with no .m code to back them do not give fine-grained memory reporting to the profiler.
I ran a couple tests for the following code:
% truncTest.m
N = 628000000;
M = 364000000;
clear Z
Z = zeros(N,1,'single');
Z(M:end) = [];
Z(1) % just because
clear Z
Z = zeros(N,1,'single');
Z = Z(1:M);
Z(1)
For what they are worth, the memory profiling results for this N
and M
are:
Well, both lines look the same in terms of memory allocated and freed. Maybe that's not the whole truth.
So, out of curiosity I decreased M
to 200
(just 200!) without changing N
, did profile clear
and reran. Profiling claims:
Interestingly, Z=Z(1:M);
is practically instantaneous now, and Z(M:end)=[];
is a little faster. Both free about 2.4GB of memory, as expected.
Finally, if we go the other direction and set M=600000000;
:
Now even Z=Z(1:M);
is slow, but about twice as fast as Z(M:end)=[];
.
This suggests:
Z=Z(1:M);
just grabs the indicated elements, stores them in a new buffer or temporary variable, releases the old buffer and assigns the new/temporary to the array Z
. I was able to make my weaker 4GB machine go from 2.45 seconds to thrashing the page file for 5 minutes just by increasing M
and leaving N
alone. Definitely prefer this option for small M/N
, probably in all cases.Z(M:end)=[];
always rewrites the buffer, and execution time increases with M
too. Actually always slower, and seems to increase exponentially, unlike Z=Z(1:M);
.UPDATE 1: Just for fun I timed the tests at a range of values of M
:
Clearly more informative than the profiling. Both methods are not no-ops, but Z=Z(1:M);
is fastest, but it can use almost double the memory of Z
for M/N
near 1.
UPDATE 2:
A relatively unknown feature
called mtic
(and mtoc
) were available in 32-bit Windows prior to R2008b. I still have it installed on one machine, so I decided to see if that provides any more insight, with the understanding that (a) much has changed since then and (b) it's a completely different memory manager used in 32-bit MATLAB. Still, I reduced the test size to N=128000000; M=101000000;
and had a look. First, feature mtic
for Z=Z(1:M-1);
>> tic; feature mtic; Z=Z(1:M-1); feature mtoc, toc
ans =
TotalAllocated: 808011592
TotalFreed: 916009628
LargestAllocated: 403999996
NumAllocs: 86
NumFrees: 77
Peak: 808002024
Elapsed time is 0.951283 seconds.
Clearing up, recreating Z
, the other way:
>> tic; feature mtic; Z(M:end) = []; feature mtoc, toc
ans =
TotalAllocated: 1428019588
TotalFreed: 1536018372
LargestAllocated: 512000000
NumAllocs: 164
NumFrees: 157
Peak: 1320001404
Elapsed time is 4.533953 seconds.
In every metric (TotalAllocated
, TotalFreed
, NumAllocs
, etc.), Z(M:end) = [];
is less efficient than Z=Z(1:M-1);
. I expect it is possible to discern what is going on in memory by examining these numbers for these values of N
and M
, but we'd be guessing about an old MATLAB
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