I am using matplotlib in interactive mode to show the user a plot that will help them enter a range of variables. They have the option of hitting "?" to show this plot, and the prompt for variables will then be repeated.
How do I know to not re-draw this plot if it's still being displayed?
Superficially, I have this clunky (pseudo-ish) code:
answer = None
done_plot = False
while answer == None:
answer = get_answer()
if answer == '?':
if done_plot:
have_closed = True
##user's already requested a plot - has s/he closed it?
## some check here needed:
have_closed = ?????
if have_closed == False:
print 'You already have the plot on display, will not re-draw'
answer = None
continue
plt.ion()
fig = plt.figure()
### plotting stuff
done_plot = True
answer = None
else:
###have an answer from the user...
what can I use (in terms of plt.gca(), fig etc...) to determine if I need to re-plot? Is there a status somewhere I can check?
Many thanks,
David
In the current versions of the IPython notebook and jupyter notebook, it is not necessary to use the %matplotlib inline function. As, whether you call matplotlib. pyplot. show() function or not, the graph output will be displayed in any case.
Asynchronous Plotting in Matplotlib: rather than call savefig directly, add plots to an asynchronous queue to avoid holding up the main program. Makes use of multiple processes to speed up the writing out.
Matplotlib is also a great place for new Python users to start their data visualization education, because each plot element is declared explicitly in a logical manner. Plotly, on the other hand, is a more sophisticated data visualization tool that is better suited for creating elaborate plots more efficiently.
In the same vein as unutbu's answer, you can also check whether a given figure is still opened with
import matplotlib.pyplot as plt
if plt.fignum_exists(<figure number>):
# Figure is still opened
else:
# Figure is closed
The figure number of a figure is in fig.number
.
PS: Note that the "number" in figure(num=…)
can actually be a string: it is displayed in the window title. However, the figure still has a number
attribute which is numeric: the original string num
value cannot be used with fignum_exists()
.
PPS: That said, subplots(…, num=<string num>)
properly recovers the existing figure with the given string number. Thus, figures are still known by their string number in some parts of Matplotlib (but fignum_exists()
doesn't use such strings).
import matplotlib.pyplot as plt
if plt.get_fignums():
# window(s) open
else:
# no windows
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