Math Round to always upper integer

Question

I need to find a division of two integers and round it to next upper integer

e.g x=7/y=5 = 2; here x and y always greater than 0

This is my current code

 int roundValue = x % y > 0? x / y + 1: x / y;

Is there any better way to do this?

Answer 1

You could use Math.Ceiling... but that will require converting to/from double values.

Another alternative is to use Math.DivRem to do both parts at the same time.

public static int DivideRoundingUp(int x, int y) {     // TODO: Define behaviour for negative numbers     int remainder;     int quotient = Math.DivRem(x, y, out remainder);     return remainder == 0 ? quotient : quotient + 1; } 

Answer 2

Try (int)Math.Ceiling(((double)x) / y)

Answer 3

All solutions looks too hard. For upper value of x/y, use this one

( x + y - 1 ) / y