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Matching vector values by records in a data frame in R

Tags:

r

sampling

I have a vector of values r as follows:

 r<-c(1,3,4,6,7)

and a data frame df with 20 records and two columns:

 id<-c(1,2,3,4,5,6,7,8,9,10,11,12,13,1,4,15,16,17,18,19,20)
 freq<-c(1,3,2,4,5,6,6,7,8,3,3,1,6,9,9,1,1,4,3,7,7)
 df<-data.frame(id,freq)

Using the r vector I need to extract a sample of records (in the form of a new data frame) from df in a way that the freq values of the records, would be equal to the values I have in my r vector. Needless to say that if it finds multiple records with the same freq values it should randomly pick one of them. For instance one possible outcome can be:

   id     frequency
   12         1
   10         3
   4          4
   7          6
   8          7

I would be thankful if anyone could help me with this.

like image 502
AliCivil Avatar asked May 01 '15 14:05

AliCivil


2 Answers

You could try data.table

library(data.table)
setDT(df)[freq %in% r,sample(id,1L) , freq]

Or using base R

aggregate(id~freq, df, subset=freq %in% r, FUN= sample, 1L)

Update

If you have a vector "r" with duplicate values and want to sample the data set ('df') based on the length of unique elements in 'r'

  r <-c(1,3,3,4,6,7)
  res <- do.call(rbind,lapply(split(r, r), function(x) {
           x1 <- df[df$freq %in% x,]
           x1[sample(1:nrow(x1),length(x), replace=FALSE),]}))
  row.names(res) <- NULL
like image 101
akrun Avatar answered Nov 02 '22 10:11

akrun


You can use filter and sample_n from "dplyr":

library(dplyr)
set.seed(1)
df %>% 
  filter(freq %in% r) %>% 
  group_by(freq) %>% 
  sample_n(1)
# Source: local data frame [5 x 2]
# Groups: freq
# 
#   id freq
# 1 12    1
# 2 10    3
# 3 17    4
# 4 13    6
# 5  8    7
like image 45
A5C1D2H2I1M1N2O1R2T1 Avatar answered Nov 02 '22 11:11

A5C1D2H2I1M1N2O1R2T1