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Mapping element-wise a NumPy array into an array of more dimensions

I want map a numpy.array from NxM to NxMx3, where a vector of three elements is a function of the original entry:

lambda x: [f1(x), f2(x), f3(x)]

However, things like numpy.vectorize do not allow to change dimensions. Sure, I can create an array of zeros and make a loop (and it is what I am doing by now), but it does not sound neither Pythonic nor efficient (as every looping in Python).

Is there a better way to perform an elementwise operation on numpy.array, producing a vector for each entry?

like image 524
Piotr Migdal Avatar asked Jun 15 '13 11:06

Piotr Migdal


2 Answers

Now that I see your code, for most simple mathematical operations you can let numpy do the looping, what is often referred to as vectorization:

def complex_array_to_rgb(X, theme='dark', rmax=None):
    '''Takes an array of complex number and converts it to an array of [r, g, b],
    where phase gives hue and saturaton/value are given by the absolute value.
    Especially for use with imshow for complex plots.'''
    absmax = rmax or np.abs(X).max()
    Y = np.zeros(X.shape + (3,), dtype='float')
    Y[..., 0] = np.angle(X) / (2 * pi) % 1
    if theme == 'light':
        Y[..., 1] = np.clip(np.abs(X) / absmax, 0, 1)
        Y[..., 2] = 1
    elif theme == 'dark':
        Y[..., 1] = 1
        Y[..., 2] = np.clip(np.abs(X) / absmax, 0, 1)
    Y = matplotlib.colors.hsv_to_rgb(Y)
    return Y

This code should run much faster than yours.

like image 158
Jaime Avatar answered Oct 21 '22 11:10

Jaime


If I understand your problem correctly, I suggest you use np.dstack:

Docstring:
Stack arrays in sequence depth wise (along third axis).

Takes a sequence of arrays and stack them along the third axis
to make a single array. Rebuilds arrays divided by `dsplit`.
This is a simple way to stack 2D arrays (images) into a single
3D array for processing.

    In [1]: a = np.arange(9).reshape(3, 3)

    In [2]: a
    Out[2]: 
    array([[0, 1, 2],
           [3, 4, 5],
           [6, 7, 8]])

    In [3]: x, y, z = a*1, a*2, a*3  # in your case f1(a), f2(a), f3(a) 

    In [4]: np.dstack((x, y, z))
    Out[4]: 
    array([[[ 0,  0,  0],
            [ 1,  2,  3],
            [ 2,  4,  6]],

           [[ 3,  6,  9],
            [ 4,  8, 12],
            [ 5, 10, 15]],

           [[ 6, 12, 18],
            [ 7, 14, 21],
            [ 8, 16, 24]]])
like image 33
root Avatar answered Oct 21 '22 10:10

root