Mapping arrays to list of objects kotlin

Question

I'm wondering about methods of mapping multiple arrays into one list of object.

I mean e.g. I have

val a = arrayOf("A1","A2","A3")
val b = arrayOf("B1","B2","B3")

and

data class SomeClass(val v1:String, val v2:String)

I want to parse it in elegant way to have list like that:

val list = listOf(SomeClass("A1","B1"),SomeClass("A2","B2"),SomeClass("A3","B3"))

I assume they are of the same length. The only way I thought of is:

val list = mutableListOf<SomeClass>() 
for (i in a.indices) 
            array.add(SomeClass(a[i],b[i])

Is there a better, more elegant solution (maybe using Collecions.zip or Array.map)?

Answer 1

Try Array.zip and then map:

val list = a.zip(b)
            .map { SomeClass(it.first, it.second) }

or if you like it more:

val list = a.zip(b)
            .map { (a, b) -> SomeClass(a, b) }

Note that if both arrays differ in size, the additional values are ignored. Note also that this will create intermediate Pairs (which is the default transformation function of zip). Even though I like the explicit map more, @hotkeys solution regarding the overloaded method is more appropriate (you spare that hidden Pair-transformation):

val list = a.zip(b) { a, b -> SomeClass(a, b) }

And where the overloaded method probably shines, is when using references instead:

a.zip(b, ::SomeClass)

Which will work as long as you have a constructor matching the zipped arguments and doesn't work out of the box for the Pair (yet?).

Answer 2

Improving on @Roland's answer, you can use the zip overload that accepts a two-argument function for mapping the pairs immediately:

val result = a.zip(b) { x, y -> SomeClass(x, y) }