I have a class User. A user can be a friend with many other users. The relationship is mutual. If A is a friend of B then B is a friend of A. Also I want every relation to store additional data - for example the date when two users became friends. So this is a many-to-many relationship on the same table with additional columns. I know that a middle class Friendship should be created(containing two user ids and column for the date). But I am coming short at mapping this with Hibernate. The thing that stops me is that the mapping is to the same table. I can solve it, if the many-to-many relationship was between two different tables.
A self-referencing many-to-many relationship exists when a given record in the table can be related to one or more other records within the table and one or more records can themselves be related to the given record.
In a One-To-Many relationship, one object is the "parent" and one is the "child". The parent controls the existence of the child. In a Many-To-Many, the existence of either type is dependent on something outside the both of them (in the larger application context).
You have said
many-to-many relationship on the same table
It is not a good idea. It is a nightmare to maintain.
Try this one instead
@Entity
public class Friend {
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
private Integer friendId;
@Column
private String name;
@OneToMany(mappedBy="me")
private List<MyFriends> myFriends;
}
@Entity
public class MyFriends {
@EmbeddedId
private MyFriendsId id;
@Column
private String additionalColumn;
@ManyToOne
@JoinColumn(name="ME_ID", insertable=false, updateable=false)
private Friend me;
@ManyToOne
@JoinColumn(name="MY_FRIEND_ID", insertable=false, updateable=false)
private Friend myFriend;
@Embeddable
public static class MyFriendsId implements Serializable {
@Column(name="ME_ID", nullable=false, updateable=false)
private Integer meId;
@Column(name="MY_FRIEND_ID", nullable=false, updateable=false)
private Integer myFriendId;
public boolean equals(Object o) {
if(o == null)
return false;
if(!(o instanceof MyFriendsId))
return false;
MyFriendsId other = (MyFriendsId) o;
if(!(other.getMeId().equals(getMeId()))
return false;
if(!(other.getMyFriendId().equals(getMyFriendId()))
return false;
return true;
}
public int hashcode() {
// hashcode impl
}
}
}
regards,
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