I'm trying to filter out strings that contain a particular character, but it doesn't work. I guess <code>make</code> does not support multiple <code>%</code> patterns? <pre class="prettyprint"><code>.PHONY: test test: echo $(filter-out %g%, seven eight nine ten) </code></pre> Gives: <pre class="prettyprint"><code>$ make test echo seven eight nine ten seven eight nine ten </code></pre> It doesn't filter out "eight"? Actually what I want to do is filter out from a list of filenames those containing "$". (In a Java context.) Any hope, or do I have to use <code>$(shell)</code>? Thanks.

Does the following function meet the purpose? <pre class="prettyprint"><code>FILTER_OUT = $(foreach v,$(2),$(if $(findstring $(1),$(v)),,$(v))) $(call FILTER_OUT,g, seven eight nine ten) </code></pre>

I recently did something similar using two <code>wildcards</code> functions for excluding some files <pre class="prettyprint"><code>.PHONY: test test: echo $(filter-out $(wildcard *g*.c),$(wildcard *.c)) </code></pre>

Makefile: Filter out strings containing a character

Q: What does Patsubst do in Makefile?

Finds whitespace-separated words in TEXT that match PATTERN and replaces them with REPLACEMENT. Here PATTERN may contain a % which acts as a wildcard, matching any number of any characters within a word.

Q: What is Makefile_list?

MAKEFILE_LIST. Contains the name of each makefile that is parsed by make , in the order in which it was parsed. The name is appended just before make begins to parse the makefile. Thus, if the first thing a makefile does is examine the last word in this variable, it will be the name of the current makefile.

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I'm trying to filter out strings that contain a particular character, but it doesn't work. I guess make does not support multiple % patterns?

.PHONY: test test:     echo $(filter-out %g%, seven eight nine ten)

Gives:

$ make test echo seven eight nine ten seven eight nine ten

It doesn't filter out "eight"? Actually what I want to do is filter out from a list of filenames those containing "$". (In a Java context.)

Any hope, or do I have to use $(shell)?

Thanks.

633

asked May 26 '11 21:05

Steve

2 Answers

Does the following function meet the purpose?

FILTER_OUT = $(foreach v,$(2),$(if $(findstring $(1),$(v)),,$(v))) $(call FILTER_OUT,g, seven eight nine ten)

124

answered Sep 24 '22 11:09

Ise Wisteria

I recently did something similar using two wildcards functions for excluding some files

.PHONY: test test:     echo $(filter-out $(wildcard *g*.c),$(wildcard *.c))

answered Sep 25 '22 11:09

bltavares

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