make typedefs incompatible

Question

Situation:

typedef int TypeA;
typedef int TypeB;

I need to make TypeA incompatible with TypeB (so any attempt to assign TypeA to TypeB would trigger compile error), while retaining all functionality provided by built-in type (operators).

One way to do it is to wrap each type into separate struct/class (and redefine all operators, etc).

Is there any other, more "elegant", way to do it?

Third party libraries are not allowed. C++0x/C++11x is not supported. (C++ 2003 is supported)

Answer 1

The only way is to create a new type (by using for example BOOST_STRONG_TYPEDEF).