Make Copy of Object Without Reference To Original [duplicate]

Question

I have a function that takes an object from a list as a parameter. I create a new instance of this object and make it equal to the object passed into the function. I change some of the properties of the new object, but these changes also get applied to the original object in the list. Example:

public void myFunction(Object original)
{
    var copyOfObject = original;

    copyOfObject.SomeProperty = 'a';
}

From reading, I guess I am creating a shallow copy of my original object, so when I update the properties on my new object this causes the properties on the original to change to? I've seen some examples of copying the entire list of objects to create a deep copy, but I only want to create a deep copy of this single object and not the entire list. Can I do this without having to do:

  copyOfObject = new Object();
  copyOfObject.someProperty = original.someProperty;

before making my changes?

Answer 1

You could apply serialize-deserialize for the object to create deep copy.

public static class ObjectExtensions
{
    public static T Clone<T>(this T obj)
    {
        return (T)JsonConvert.DeserializeObject(JsonConvert.SerializeObject(obj));
    }
}

Then usage;

public void myFunction(Object original)
{
    var copyOfObject = original.Clone();
}