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I am trying to validate a (US) phone number with no extra characters in it. so the format is 1-555-555-5555 with no dashes, spaces, etc and the 1 is optional. However, my regular expression will ONLY except numbers with the leading 1 and says numbers without it are invalid. Here is what I am using where did I go wrong?
"^(1)\\d{10}$" 
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for metacharacters such as \d (digit), \D (non-digit), \s (space), \S (non-space), \w (word), \W (non-word). to escape special regex characters, e.g., \. for . , \+ for + , \* for * , \? for ? . You also need to write \\ for \ in regex to avoid ambiguity.
$ means "Match the end of the string" (the position after the last character in the string).
RegEx makes replace ing strings in JavaScript more effective, powerful, and fun. You're not only restricted to exact characters but patterns and multiple replacements at once.
So to make any group optional, we need to have to put a “?” after the pattern or group. This question mark makes the preceding group or pattern optional. This question mark is also known as a quantifier.
Use:
"^1?\\d{10}$" The ? means "optional".
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