In the absence of help from Google, I wonder if someone could tell me if it is possible to create a C++ (g++) debug macro that acts like, for example, an "improved" std::cout. Idea is to accept args via << and to append some text so that
DBG << "Hello" << world;
might produce
myfile.cpp 1420 Hello world
I know there are logging libraries(?)/macros(?) out there that do this sortof thing. I'm interested in how it's done, not using some package.
Your macro could create a temporary variable which invokes endl
on destruction. The temporary will stick around until the enclosing expression ends, typically at the ;
.
#include <iostream>
struct X {
~X() { std::cout << std::endl; }
};
#define DBG (X(), std::cout << __FILE__ << " " << __LINE__ << " ")
int main () {
std::string world(", world");
DBG << "Hello" << world;
}
How about:
#define DBG std::cout << __FILE__ << " " << __LINE__ << " "
http://ideone.com/mN5n3
Close enough! Unfortunatelly, you have to declare the variable world
beforehand.
The idea behind a debug macro is that it should compile to nothing if you are in release mode. Try this;
#ifdef _DEBUG
#define MESSAGE(x) (std::cout << __FILE__ << " " << __LINE__ << " " << x);
#else
#define MESSAGE(x) ;
#endif
int _tmain(int argc, _TCHAR* argv[])
{
MESSAGE("Hello");
return 0;
}
When you are in release mode, MESSAGE(x)
will have no effect, but in debug mode, you will get a message to the command line.
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