Lua Table Sorting 2 compares

Question

I have gone over as many of the answers here as I could find that had titles I considered near enough to my problem to look into. I haven't seen anyone having my exact issue, so I'm asking a question I hope is just me being ignorant to a simple fact.

I'm trying to code a table that records HP (int) and the distance (boolean) and then sort by HP with only the ones in Range near the top.

local tableTest = {
    {hp = 64, range = true, name="Frank"},
    {hp = 100, range = true, name="Joe"},
    {hp = 2, range = false, name="Jim"},
    {hp = 76, range = true, name="Tim"},
    {hp = 17, range = false, name="Jill"},
    {hp = 16, range = true, name="Phillip"},
}

-- Sort by HP and Range to find lowest Unit in Range.
table.sort(tableTest, function(x,y) return x.hp < y.hp and x.range end)

for i=1, #tableTest do print(tableTest[i].name, tableTest[i].hp) end

The output for this is:

Phillip 16
Jim     2
Frank   64
Jill    17
Tim     76
Joe     100

The output I was expecting from this would be:

Phillip 16
Frank   64
Tim     76
Joe     100
Jim     2
Jill    17

I pray this is just a misunderstanding on my part of how the table.sort works with multiple checks like this (I assumed it was closer to how you declare a variable like this).

edit Additional information - If I change the order of where the range=false indexes are located in the table, the output changes as well (still incorrect). The values just sort themselves into different indexes after the sort.

Answer 1

According to your description, your order function needs to compare range first, then compare hp.

table.sort(tableTest, function(x,y) 
                          if x.range and y.range then return x.hp < y.hp 
                          elseif x.range then return true
                          elseif y.range then return false
                          else return x.hp < y.hp end
                      end)

Maybe there is some shorter version, but this one sure works and the logic is clear.