Losing 0 for single-digit hours with golang time package

Question

I'm trying to format a series a date such as:

• March 12th, 2013, 3pm looks like : 2013-03-12-15.txt
• March 12th, 2013, 4am looks like : 2013-03-12-4.txt

Using golang and the Time package

package main

import (
    "time"
    "fmt"
)

const layout = "2006-01-02-15.txt"

func main() {
    t := time.Date(2013, time.March, 12, 4, 0, 0, 0, time.UTC)
    fmt.Println(t.Format(layout))
}

Which unfortunately add a zero in front of the single-digit hour : 2013-03-12-04.txt

Is there an idiomatic way to reach the desired output, or I must tweak myself something with the String package ?

Thanks in advance for your help !

Answer 1

In case you need 24-hour format and don't want the leading zero for hour < 10 I only see a custom string format:

date := fmt.Sprintf("%d-%d-%d-%d", t.Year(), t.Month(), t.Day(), t.Hour())

Of course not an idiomatic way to format a date in Go.

Update (thanks for the comment):

t := time.Now() 
date := fmt.Sprintf("%s-%d.txt", t.Format("2006-01-02"), t.Hour())
fmt.Println(date)