Loop over 256 values using 8-bit unsigned integer variable as counter

Question

So I was just trying to fill a buffer with consecutive numbers 0-255. I didn't think much on it and ended up in an infinite loop.

uint8_t i;
uint8_t txbuf[256];

for (i=0; i<256; i++) {
    txbuf[i] = i;
}

the problem being that i will never be 256 as it rolls over to zero after 255.

my question is, is there a way to do this loop without bumping i up to a 16 bit value?

Note: I know I could change the loop to i<255 and add another line for the final spot but I'm trying to figure out of there is a nicer looking way.

Answer 1

uint8_t txbuf[256];
uint8_t i = 0;

do {
   txbuf[i] = i;  
} while (i++ != 255);

or

uint8_t txbuf[256];
uint8_t i = 255; 

do {
   txbuf[i] = i;  
} while (i--);