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Logging into facebook with python

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python

If I run the following code 10 times in a row, it will work about half the time and fail the rest. Anyone know why?

import urllib2, cookielib, re, os, sys

class Facebook():
    def __init__(self, email, password):
        self.email = email
        self.password = password

        cj = cookielib.CookieJar()
        opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj))
        opener.addheaders = [('Referer', 'http://login.facebook.com/login.php'),
                            ('Content-Type', 'application/x-www-form-urlencoded'),
                            ('User-Agent', 'Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.1.7) Gecko/20091221 Firefox/3.5.7 (.NET CLR 3.5.30729)')]
        self.opener = opener

    def login(self):
        url = 'https://login.facebook.com/login.php?login_attempt=1'
        data = "locale=en_US&non_com_login=&email="+self.email+"&pass="+self.password+"&lsd=20TOl"

        usock = self.opener.open('http://www.facebook.com')
        usock = self.opener.open(url, data)
        if "Logout" in usock.read():
            print "Logged in."
        else:
            print "failed login"
            print usock.read()
            sys.exit()

f = Facebook("[email protected]", "asdfasdf")
f.login()
like image 232
tehryan Avatar asked Nov 30 '22 06:11

tehryan


1 Answers

So I tried your code, and got it to log in once, then like you I had trouble logging in again. On a line before the 'if' statement, I added print usock.read() and ended up getting a bunch of html code. I then dropped that code into a notepad, saved it as an html file, and pulled it up. This is what's happening: Facebook gets suspicious that we're logging in from a computer program, and is waiting for us to verify that we're real by showing a captcha word. The program doesn't account for this, and prints "Failed login" when it's really more of a pending login.

like image 100
K. Murray Avatar answered Dec 05 '22 03:12

K. Murray