why doesn't it exist?
import math [x for x in dir(math) if 'log' in x] >>> ['log', 'log10', 'log1p']
I know I can do log(x,2), but log2 is really common, so I'm kind of baffled.
Oh, it looks like it's only defined in C99, not C90, I guess that answers my question. Still seems kind of silly.
log2(a) : This function is used to compute the logarithm base 2 of a. Displays more accurate result than log(a,2). Syntax : math. log2(a) Parameters : a : The numeric value Return Value : Returns logarithm base 2 of a Exceptions : Raises ValueError if a negative no. is passed as argument.
The math. log2() method returns the base-2 logarithm of a number.
Log2 Calculation The log base 2, also known as the binary logarithm uses the number 2 as the base. The log2 of a number n is the power to which the number 2 must be raised to obtain the value n. For example, the binary logarithm of 1 is 0, 2 is 1, 8 is 3 and 32 is 5.
The log2() function returns the base-2 logarithm of a number.
I think you've answered your own question. :-) There's no log2(x)
because you can do log(x, 2)
. As The Zen of Python (PEP 20) says, "There should be one-- and preferably only one --obvious way to do it."
That said, log2
was considered in Issue3366 (scroll down to the last 3 messages) which added several other C99 math functions to the math
module for Python 2.7 and 3.2.
Edit: log2 was reconsidered in Issue11888 and added in Python 3.3.
I'm not sure that there is that you want, but:
-- From math point of view you can do for example math.log(x)/math.log(2).
-- If input X has an integral type and you are waiting for the integral rounded result - you can do it rather faster with right shifting. This works with SHR command and without Taylor series + local interpolation, which is under the hood of libc log() calls.
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