time_t rawtime; struct tm * timeinfo; time ( &rawtime ); timeinfo = localtime ( &rawtime );
This returns: warning C4996: 'localtime': This function or variable may be unsafe. Consider using localtime_s instead.
time_t rawtime; struct tm * timeinfo; time ( &rawtime ); timeinfo = localtime_s ( &rawtime );
When I change localtime to localtime_s I get: error C2660: 'localtime_s' : function does not take 1 arguments
Here is what I think is going on in the first block of code:
convert the rawtime into something meaningful to pedestrians
localtime
returns a pointer to a statically allocated struct tm
.
With localtime_s, you pass in a pointer to a struct tm, and localtime_s
writes its result data into that, so your code would change from:
struct tm *timeinfo; timeinfo = localtime(&rawtime);
to something like:
struct tm timeinfo; localtime_s(&timeinfo, &rawtime);
This way, it's writing to your buffer instead of having a buffer of its own.
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