Local initial values are stored at?

Question

#include <stdio.h>  
int main()
{
  int i = 10;
  return 0;
}

In the above program, where exactly the value 10 is stored ?

I understand the variable i is stored in the stack. stack is populated during run time. From "where exactly" 10 is coming from.

Answer 1

10 is a constant, so the compiler will use the number 10 directly in the executable part of your program as part of the CPU instructions.

Here's the assembly produced on my system with gcc:

movl    $10, -4(%rbp)

(The 4 is because an int is 4 bytes long)

Note that all of these things are part of the implementation, but the above happens in practice. The language itself doesn't specify these details.

Answer 2

10 is a "literal", which will be generated by the compiler during compilation. And then it will be assigned to your variable on the stack. Like

mov eax, 10;
mov [0x12345678], eax;

This is pseude-code, though, but will assign your variable i (address is here 0x12345678) the value 10, previously stored in eax.