Load, modify, and write an XML document in Groovy

Question

I have an XML document that I want to load from a file, modify a few specific elements, and then write back to disk.

I can't find any examples of how to do this in Groovy.

Answer 1

You can just modify the node's value property to modify the values of elements.

/* input: <root>   <foo>     <bar id="test">       test     </bar>     <baz id="test">       test     </baz>   </foo> </root> */  def xmlFile = "/tmp/test.xml" def xml = new XmlParser().parse(xmlFile) xml.foo[0].each {      it.@id = "test2"     it.value = "test2" } new XmlNodePrinter(new PrintWriter(new FileWriter(xmlFile))).print(xml)  /* output: <root>   <foo>     <bar id="test2">       test2     </bar>     <baz id="test2">       test2     </baz>   </foo> </root> */ 

Answer 2

If you want to use the XmlSlurper:

//Open file def xml = new XmlSlurper().parse('/tmp/file.xml')  //Edit File e.g. append an element called foo with attribute bar xml.appendNode {    foo(bar: "bar value") }  //Save File def writer = new FileWriter('/tmp/file.xml')  //Option 1: Write XML all on one line def builder = new StreamingMarkupBuilder() writer << builder.bind {   mkp.yield xml }  //Option 2: Pretty print XML XmlUtil.serialize(xml, writer) 

Note: XmlUtil can also be used with the XmlParser as used in @John Wagenleitner's example.

References:

• Option 1
• Option 2