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I'm trying to pass a list of arguments with argparse but the only way that I've found involves rewriting the option for each argument that I want to pass:
What I currently use:
main.py -t arg1 -a arg2
and I would like:
main.py -t arg1 arg2 ...
Here is my code:
parser.add_argument("-t", action='append', dest='table', default=[], help="")
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Multiple Input Arguments Using the nargs parameter in add_argument() , you can specify the number (or arbitrary number) of inputs the argument should expect. In this example named sum.py , the --value argument takes in 3 integers and will print the sum.
All parameters should be passed as keyword arguments. Each parameter has its own more detailed description below, but in short they are: prog - The name of the program (default: os.path.basename(sys.argv[0]) ) usage - The string describing the program usage (default: generated from arguments added to parser)
The return value from parse_args() is a Namespace containing the arguments to the command. The object holds the argument values as attributes, so if your argument dest is "myoption", you access the value as args.
Use nargs:
ArgumentParser objects usually associate a single command-line argument with a single action to be taken. The nargs keyword argument associates a different number of command-line arguments with a single action.
For example, if nargs is set to '+'
Just like
'*', all command-line args present are gathered into a list. Additionally, an error message will be generated if there wasn’t at least one command-line argument present.
So, your code would look like
parser.add_argument('-t', dest='table', help='', nargs='+')
That way -t arguments will be gathered into list automatically (you don't have to explicitly specify the action).
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