List comprehensions of dictionary values

Question

I am new to Python and I am trying to learn manipulating a dictionary. I have a dict that has the following structure:

dict = {'city1':([1990, 1991, 1992, 1993],[1.5,1.6,1.7,1.8]),
        'city2':([1993, 1995, 1997, 1999],[2.5,3.6,4.7,5.8])   

I would like convert the key of in the following way

 'city': ([1990, 1.5],[1991, 1.6],[1992,1.7],[1993,1.8])

I tried using a for loop to loop through the values and create a new value for each key. However, this seems really slow and clumsy. Is there any Pathonic way of achieving this goal?

Thanks!

Answer 1

You can try the following code

a = [[a, b] for a, b in zip(dict['city1'][0], dict['city1'][1])]

Output

[[1990, 1.5], [1991, 1.6], [1992, 1.7], [1993, 1.8]]

Answer 2

You can try this:

d = {'city1':([1990, 1991, 1992, 1993],[1.5,1.6,1.7,1.8]),
    'city2':([1993, 1995, 1997, 1999],[2.5,3.6,4.7,5.8])}   

new_dict = {a:tuple(map(list, zip(b[0], b[1]))) for a, b in d.items()}

Output:

{'city2': ([1993, 2.5], [1995, 3.6], [1997, 4.7], [1999, 5.8]), 'city1': ([1990, 1.5], [1991, 1.6], [1992, 1.7], [1993, 1.8])}