I'm thinking if there is a way that when I merge a branch into another branch that ALL changed files are listed in my commit message and not just the ones which were modified in both branches. This would give me a better overview of what was changed in the branch just by seeing the merge commit. Is there a way to do this?
Fast forward merge can be performed when there is a direct linear path from the source branch to the target branch. In fast-forward merge, git simply moves the source branch pointer to the target branch pointer without creating an extra merge commit.
To find out which files changed in a given commit, use the git log --raw command. It's the fastest and simplest way to get insight into which files a commit affects.
Fast-forward merges literally move your main branch's tip forward to the end of your feature branch. This keeps all commits created in your feature branch sequential while integrating it neatly back into your main branch.
By default, Git does not create an extra merge commit when merging a commit that is a descendant of the current commit. Instead, the tip of the current branch is fast-forwarded.
I don't know how to do that in the commit message. But after the merge, this will give the names of all the files affected by the merge commit:
git log -m --name-only
For only a list of filenames of the commit:
git log -m -1 --name-only --pretty="format:" <Merge SHA>
There is some white space due to the merge having two parents but that can be easily removed.
You can also use the diff
command to see the difference between any two commits. If the branches haven't been merged yet, you can specify the branch names and compare them, otherwise you might need to find where they diverged (like so) an the last commit before they were merged back together.
git diff --name-status <commit> <commit>
-name-status
Show only names and status of changed files.
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