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I have a very large log file (6 gig).
I want to search for 'Nov 12 2012' and print off each line.
I'm a linux novice and have no idea how this is done. Mostly likely will need a more option to view X number of lines and move forward thru the search.
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The grep command prints entire lines when it finds a match in a file. To print only those lines that completely match the search string, add the -x option. The output shows only the lines with the exact match.
To also show you the lines before your matches, you can add -B to your grep. The -B 4 tells grep to also show the 4 lines before the match. Alternatively, to show the log lines that match after the keyword, use the -A parameter. In this example, it will tell grep to also show the 2 lines after the match.
With grep -i -n 'string' you can search for a particular string and find out what line it is on.
grep --after-context=5 --before-context=10 'Nov 12 2012' yourfile.log That'll show each line that contains your date text, as well as 10 lines of text BEFORE the line that matched, and 5 lines AFTER the line that matched.
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You can use grep to show matching lines and less as a pager:
grep 'Nov 12 2012' /path/to/logfile | less Type 'space' at the end of each page to advance to the next screen of results.
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