Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

LINQ: Remove Element from XML based on attribute value?

How can I remove any element in xml based on matched attribute value?

Here is my XML :

<Projects>
    <Project serverUrl="tcp://xyz1:xxx/sdfsdf.rem" projectName="project1" />
    <Project serverUrl="tcp://xyz2:xxx/sdfsdf.rem" projectName="project2" />
    <Project serverUrl="tcp://xyz3:xxx/sdfsdf.rem" projectName="project3" />
    <Project serverUrl="tcp://xyz4:xxx/sdfsdf.rem" projectName="project4" />
    <Project serverUrl="tcp://xyz5:xxx/sdfsdf.rem" projectName="project5" />
    <Project serverUrl="tcp://xyz6:xxx/sdfsdf.rem" projectName="project6" />
   </Projects>

I am using the following LINQ query:

var remove = from elemet in xdoc.Elements("Projects").Elements("Project")
                                 where elemet.Attribute("projectName").Value == "project1"
                                 select elemet.Parent.Remove();

I am getting compile time error on select as :

The type of expression in select clause is Incorrect

EDIT ANSWER: this one works for me. Thanks All

var xElement = (from elemet in xdoc.Elements("Projects").Elements("Project")
                            where elemet.Attribute("projectName").Value == foundProject
                            select elemet);
            xElement.Remove();
like image 581
PawanS Avatar asked Feb 15 '11 13:02

PawanS


4 Answers

Remove is a (void) method call, not a function that can return a value. You probably want something like this:

var elementsToRemove = from elemet in xdoc.Elements("Projects").Elements("Project")
                       where elemet.Attribute("projectName").Value == "project1"
                       select elemet;

foreach (var e in elementsToRemove)
    e.Remove();

LINQ is a query language, it's (mainly) used to return something. Performing actions on these elements is usually a separate step.

like image 102
Heinzi Avatar answered Oct 22 '22 08:10

Heinzi


You could use

xdoc.Elements("Projects").Elements("Project").Where(
                    elemet => elemet.Attribute("projectName").Value == "project1")
.ToList().ForEach(i => i.Remove());

or

(from elemet in xdoc.Elements("Projects").Elements("Project")
                          where elemet.Attribute("projectName").Value == "project1"
                          select elemet).ToList().ForEach(i => i.Remove());
like image 36
Bala R Avatar answered Oct 22 '22 06:10

Bala R


You can use the following code snippet:

xdoc.XPathSelectElement("Projects/Project[@projectName = 'project1']").Remove();
like image 28
Igor Korkhov Avatar answered Oct 22 '22 06:10

Igor Korkhov


Remove() is a method you call on an XNode. Your query is trying to select the method which doesn't make any sense.

What you actually want to do is select the item you wish to remove, then call the Remove() method on the selected item. You can find an example here: XNode.Remove Method

like image 34
Ocelot20 Avatar answered Oct 22 '22 07:10

Ocelot20