Linking in react native can open just one app

Question

UPDATE 1

I removed return from code and now links work on IOS. But on android I can't open any app. Any idea?

I am trying to open different apps from my app.

return Linking.openURL(“twitter://“);
return Linking.openURL(“instagram://“);

But it doesn’t work. I configured IOS by documentation. On android doesn’t work too. While...

return Linking.openURL(“tripadvisor://“);

Work just fine. Any idea why I can’t open other apps.
This is code that I am using (open app if installed or open store with it but sometimes even store doesn't open) what I did wrong:

let appUrl = "instagram://";
Linking.canOpenURL(appUrl).then(supported => {
            if (!supported) {
              Alert.alert("",
                "",
                [
                  {text: "go to store", onPress: this.openStorePress},
                  {text: "cancel", onPress: () => { }, style: 'cancel'},
                ],
                { cancelable: false }
              );
            } else {
              return Linking.openURL(appUrl);
            }
        }).catch(err => {
            console.error(err);
        });

Answer 1

You have to find the rights URL schemes. Have look at my code

Instagram

Linking.openURL('instagram://user?username=apple')
  .catch(() => {
    Linking.openURL('https://www.instagram.com/apple');
  })

Twitter

Linking.openURL('twitter://user?screen_name=apple')
  .catch(() => {
    Linking.openURL('https://www.twitter.com/apple');
  })

Facebook

Linking.openURL('fb://page/PAGE_ID');
Linking.openURL('http://instagram.com/_u/USER_NAME');
Linking.openURL('http://instagram.com/_p/PICTURE');

Answer 2

Your code looks pretty solid, here's an example of how I open twitter in my app.

const twitterUrlScheme = `twitter://user?screen_name=${twitterUsername}`;

Linking.canOpenURL(twitterUrlScheme)
    .then((supported) =>
        Linking.openURL(
            supported
                ? twitterUrlScheme
                : `https://www.twitter.com/${twitterUsername}`
            )
        )
        .catch((err) => console.error('An error occurred', err));

I think perhaps your issue might be the return Linking.openUrl, I'm not sure you need the return in that statement. Does it work if you remove the return? Otherwise, it might help to move your Alert outside of the then-block from canOpenUrl.