In the code below you'll see it asking for a 'shift' value. My problem is that I want to limit the input to 1 through 26.
For char in sentence:
if char in validLetters or char in space: #checks for
newString += char #useable characters
shift = input("Please enter your shift (1 - 26) : ")#choose a shift
resulta = []
for ch in newString:
x = ord(ch) #determines placement in ASCII code
x = x+shift #applies the shift from the Cipher
resulta.append(chr(x if 97 <= x <= 122 else 96+x%122) if ch != \
' ' else ch) # This line finds the character by its ASCII code
How do I do this easily?
Another implementation:
shift = 0
while not int(shift) in range(1,27):
shift = input("Please enter your shift (1 - 26) : ")#choose a shift
Use a while
loop to keep asking them for input until you receive something you consider valid:
shift = 0
while 1 > shift or 26 < shift:
try:
# Swap raw_input for input in Python 3.x
shift = int(raw_input("Please enter your shift (1 - 26) : "))
except ValueError:
# Remember, print is a function in 3.x
print "That wasn't an integer :("
You'll also want to have a try-except
block around the int()
call, in case you get a ValueError
(if they type a
for example).
Note if you use Python 2.x, you'll want to use raw_input()
instead of input()
. The latter will attempt to interpret the input as Python code - that can potentially be very bad.
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