I'm generating, let's say, the following range:
IntStream.iterate(1, i -> 3*i)
How do I limit the stream to a specific element value e.g. 100 (not elements count with limit())?
Thank you!
UPDATE the function can be arbitrary
If you can’t use Java 9 yet, you can use the following reimplementation of the three-arg IntStream.iterate
:
public static IntStream iterate(int seed, IntPredicate hasNext, IntUnaryOperator next) {
Objects.requireNonNull(next); Objects.requireNonNull(hasNext);
return StreamSupport.intStream(
new Spliterators.AbstractIntSpliterator(
Long.MAX_VALUE, Spliterator.ORDERED|Spliterator.NONNULL) {
private IntUnaryOperator op = i -> { op = next; return i; };
private int value = seed;
@Override
public boolean tryAdvance(IntConsumer action) {
Objects.requireNonNull(action);
if(op == null) return false;
int t = op.applyAsInt(value);
if(!hasNext.test(t)) { op = null; return false; }
action.accept(value = t);
return true;
}
@Override
public void forEachRemaining(IntConsumer action) {
Objects.requireNonNull(action);
IntUnaryOperator first = op;
if(first == null) return;
op = null;
for(int t = first.applyAsInt(value); hasNext.test(t); t = next.applyAsInt(t))
action.accept(t);
}
}, false);
}
It works similar to Java 9’s IntStream.iterate
, except that you have to change the class you’re invoking the static
method on (or adapt the import static
statement):
iterate(1, i -> i < 100, i -> i*3).forEach(System.out::println);
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