My code is in test.c:
int main(){
return 0;
}
The dynamically shared libraries the executable compiled from it depends on are:
$ gcc -o test test.c
$ ldd test
linux-gate.so.1 => (0x00783000)
libc.so.6 => /lib/libc.so.6 (0x00935000)
/lib/ld-linux.so.2 (0x00ea5000)
main
belong to? /lib/libc.so.6?return
belong to? /lib/libc.so.6?Thanks!
linux-gate.so
isn't really a shared lib, but a part of the kernel that acts like one and makes fast system calls possible. ld-linux.so
is a piece of code that makes loading other shared libraries possible. libc.so
is the C library, containing standard functions like printf
and strcpy
.main
doesn't belong to any library. It belongs to your program, in the sense that its assembled version is stored entirely in the test
binary file.return
is not a function but a C language construct.libgcc
, which is apparently not a shared library on your system (or it would show up) and some startup code. g++
would additionally link in libstdc++.so
(the C++ standard library) and libm.so
(the math part of the C standard library).linux-gate
is a virtual shared object that acts as a connection to system calls within the kernel. libc
is glibc, which provides functions such as printf()
and so on. ld-linux
is the glibc loader, which allows loading of other shared objects.
main()
belongs to your code. It is called by crt1.o
which is linked into the executable by gcc (well, ld specifically).
return
is not a function but rather a language construct, so gcc turns it directly into code contained within the object (and eventually executable) file. As an aside, the value returned from main()
is caught by crt1.o
and turned into a program result code.
Exelent description about how does linux execute my main()? There you will find the answer and probably a lot more!
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