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Lexical cast from string to type

Tags:

python

casting

Recently, I was trying to store and read information from files in Python, and came across a slight problem: I wanted to read type information from text files. Type casting from string to int or to float is quite efficient, but type casting from string to type seems to be another problem. Naturally, I tried something like this:

var_type = type('int') 

However, type isn't used as a cast but as a mechanism to find the type of the variable, which is actually str here.

I found a way to do it with:

var_type = eval('int') 

But I generally try to avoid functions/statements like eval or exec where I can. So my question is the following: Is there another pythonic (and more specific) way to cast a string to a type?

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Morwenn Avatar asked Aug 02 '12 10:08

Morwenn


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2 Answers

I like using locate, which works on built-in types:

>>> from pydoc import locate >>> locate('int') <type 'int'> >>> t = locate('int') >>> t('1') 1 

...as well as anything it can find in the path:

>>> locate('datetime.date') <type 'datetime.date'> >>> d = locate('datetime.date') >>> d(2015, 4, 23) datetime.date(2015, 4, 23) 

...including your custom types:

>>> locate('mypackage.model.base.BaseModel') <class 'mypackage.model.base.BaseModel'> >>> m = locate('mypackage.model.base.BaseModel') >>> m() <mypackage.model.base.BaseModel object at 0x1099f6c10> 
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dannymac Avatar answered Sep 20 '22 17:09

dannymac


You're a bit confused on what you're trying to do. Types, also known as classes, are objects, like everything else in python. When you write int in your programs, you're referencing a global variable called int which happens to be a class. What you're trying to do is not "cast string to type", it's accessing builtin variables by name.

Once you understand that, the solution is easy to see:

def get_builtin(name):     return getattr(__builtins__, name) 

If you really wanted to turn a type name into a type object, here's how you'd do it. I use deque to do a breadth-first tree traversal without recursion.

def gettype(name):     from collections import deque     # q is short for "queue", here     q = deque([object])     while q:         t = q.popleft()         if t.__name__ == name:             return t         else:             print 'not', t          try:             # Keep looking!             q.extend(t.__subclasses__())         except TypeError:             # type.__subclasses__ needs an argument, for whatever reason.             if t is type:                 continue             else:                 raise     else:         raise ValueError('No such type: %r' % name) 
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bukzor Avatar answered Sep 19 '22 17:09

bukzor