Launching with UIApplicationShortcutItem

Question

I'm implementing some 3D touch quick actions for my iOS 9 app in swift, and I have a curious issue. When my app is in the background and I launch with the quick action, everything goes as planned. When my app is totally dead (i.e. I killed it from the multitasking menu), and I launch with the quick action, the app crashes. I'm having trouble debugging this as once I kill the app, the debug session in Xcode gets detached. Is there a way for me to connect to the app to debug like normal, or is there something in my code that would be causing it? Thanks in advance.

Code:

func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool
{
    var launchedFromShortCut = false

    //Check for ShortCutItem
    if let shortcutItem = launchOptions?[UIApplicationLaunchOptionsShortcutItemKey] as? UIApplicationShortcutItem
    {
        launchedFromShortCut = true
        self.handleShortCutItem(shortcutItem)
    }

    return !launchedFromShortCut
}

func application(application: UIApplication, performActionForShortcutItem shortcutItem: UIApplicationShortcutItem, completionHandler: (Bool) -> Void)
{
    self.handleShortCutItem(shortcutItem)
}

func handleShortCutItem(shortcutItem: UIApplicationShortcutItem)
{
    //Get type string from shortcutItem
    if let shortcutType = ShortcutType.init(rawValue: shortcutItem.type)
    {
        //Get root navigation viewcontroller and its first controller
        let rootNavigationViewController = window!.rootViewController as? UINavigationController


        if let rootViewController = rootNavigationViewController?.viewControllers.first as! LaunchViewController?
        {
            //Pop to root view controller so that approperiete segue can be performed
            rootNavigationViewController?.popToRootViewControllerAnimated(false)

            switch shortcutType
            {
                case .Compose:
                    rootViewController.shouldCompose()
                    break
            }
        }
    }
}

Thanks!

Answer 1

1. In Xcode, open Product -> Schemes -> Edit Schemes
2. In your Run Scheme, change the Launch setting to 'Wait for executable to be launched'

Now, if you turn on debugging and run your app, Xcode will wait for you to launch your app from the home screen so you are able to test launching it using a 3D Touch Shortcut Item.

Answer 2

I finally got this working. Here's what my AppDelegate.swift file ended up as;

class AppDelegate: UIResponder, UIApplicationDelegate {

// Properties
var window: UIWindow?
var launchedShortcutItem: UIApplicationShortcutItem?

func applicationDidBecomeActive(application: UIApplication) {

    guard let shortcut = launchedShortcutItem else { return }

    handleShortcut(shortcut)

    launchedShortcutItem = nil

}

func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {

    // Override point for customization after application launch.
    var shouldPerformAdditionalDelegateHandling = true

    // If a shortcut was launched, display its information and take the appropriate action
    if let shortcutItem = launchOptions?[UIApplicationLaunchOptionsShortcutItemKey] as? UIApplicationShortcutItem {

        launchedShortcutItem = shortcutItem

        // This will block "performActionForShortcutItem:completionHandler" from being called.
        shouldPerformAdditionalDelegateHandling = false

    }

    return shouldPerformAdditionalDelegateHandling
}


func handleShortcut( shortcutItem:UIApplicationShortcutItem ) -> Bool {

    // Construct an alert using the details of the shortcut used to open the application.
    let alertController = UIAlertController(title: "Shortcut Handled", message: "\"\(shortcutItem.localizedTitle)\"", preferredStyle: .Alert)
    let okAction = UIAlertAction(title: "OK", style: .Default, handler: nil)
    alertController.addAction(okAction)

    // Display an alert indicating the shortcut selected from the home screen.
    window!.rootViewController?.presentViewController(alertController, animated: true, completion: nil)

    return handled

}

func application(application: UIApplication, performActionForShortcutItem shortcutItem: UIApplicationShortcutItem, completionHandler: (Bool) -> Void) {

    completionHandler(handleShortcut(shortcutItem))

}

Much of this was taken from Apple's sample code for UIApplicationShortcuts, and while I'm having my app launch an alert to prove that it is recognizing the proper shortcut was chosen, this could be adapted to your code to pop the view controller.

I think the func applicationDidBecomeActive was the critical part that I was missing, and removing the self.handleShortCut(shortcutItem) from didFinishLaunchingWithOptions (otherwise it was calling handleShortCut twice, it seemed).

Answer 3

For Swift 4.2

   func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {
    // Override point for customization after application launch.
    var isLaunchedFromQuickAction = false
    if let shortcutItem = launchOptions?[UIApplication.LaunchOptionsKey.shortcutItem] as? UIApplicationShortcutItem {
        isLaunchedFromQuickAction = true
        handleQuickAction(shortcutItem: shortcutItem)
    }

    return isLaunchedFromQuickAction
}