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last-child and last-of-type not working in SASS

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How would you write this to be SASS compliant?

.fader { display: inline-block; } .fader img:last-child {     position: absolute;     top: 0;      left: 0;     display: none; }​ 

Basically I'm just replicating this example of fading in one image over another (found here.)

His JFiddle example: http://jsfiddle.net/Xm2Be/3/

However his example is straight CSS, I'm working on a project in SASS and am not sure about how to correctly translate it.

My Code

Note in my example below, the img hover isn't working correctly (both images are showing up and no rollover fadein action happens)

My CodePen: http://codepen.io/leongaban/pen/xnjso

I tried

.try-me img:last-child & .tryme img:last-of-type 

But the : throws SASS compile errors, the code below works

.try-me img last-of-type {     position: absolute;     top: 0;      left: 0;     display: none; } 

However it spits out CSS which doesn't help me:

.container .home-content .try-me img last-of-type {     position: absolute;     top: 0;     left: 0;     display: none; } 

UPDATE: Working Codepen:

http://codepen.io/leongaban/pen/xnjso

like image 587
Leon Gaban Avatar asked Jun 03 '13 20:06

Leon Gaban


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How do you use the nth child in Sass?

Writing Complex :nth-child() SelectorsIt works exactly the same as :nth-child except that it starts from the end of the parent. For example, you can select the first three children of a parent by using the selector :nth-child(-n + 3) . You can use :nth-last-child(-n + 3) to select the last three.


2 Answers

Nesting is not a requirement with Sass. Don't feel obligated to do so if there's no need to break up the selectors.

.try-me img:last-of-type {     position: absolute;     top: 0;      left: 0;     display: none; } 

If you are applying styles to the image and then specific styles to the last-of-type, then this what it would look like when you nest it:

.try-me img {     // styles      &:last-of-type {         position: absolute;         top: 0;          left: 0;         display: none;     } } 
like image 63
cimmanon Avatar answered Oct 12 '22 12:10

cimmanon


Neither of the above worked for me, so.

last-of-type only plays nice with elements, you can select things with classes all you like but this gets handled by the elements. So say you have the following tree:

<div class="top-level">     <div class="middle"></div>     <div class="middle"></div>     <div class="middle"></div>     <div class="somethingelse"></div> </div> 

To get to the last div with the class of middle, doesn't work using last-of-type.

My workaround was to simply change the type of element that somethingelse was

Hope it helps someone out, took me a while to figure that out.

like image 31
WebTim Avatar answered Oct 12 '22 11:10

WebTim