i have codeigniter background. Now, i'm learning about laravel. So, i'm in this condition (Example), I'm trying to create a webapp, which has multiple users. The UsersType A , they can access menu a, menu b & menu c and UsersType B they only can access Menu a.
Now, i'm using https://github.com/lavary/laravel-menu . Well, if it's only have two types , i can write it manually. But, what if there are five types of user or more.
When i'm using codeigniter. I create 4 table Users
, UsersType
, Menu
& MenuAccess
. You must be understand how it's work. I just, play it with query then i show it.
UsersType (Users) -> TypeId (UsersType) -> MenuId (MenuAccess) -> MenuId (Menu)
I already use google and I found this https://github.com/Zizaco/entrust
but what i can see from that package. It's only give the permission on the action (input,edit & delete)
So, Can i do my codeigniter way in my laravel ? Save my routes properties than show it in my rouotes/web.php
(I don't know if it possible, haven't try it yet). sorry for my english.
What I would do is put a function in the User class which checks it's own permission and then returns a view which contains the menu that user has access to.
public function menu()
{
switch($this->role) {
case 'admin':
return view('menus.admin');
[etc]
}
}
Then in the view just check if the user is logged in and show the menu:
@if Auth::check()
{{ Auth::user->menu() }}
@endif
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With