Laravel - How to get the guard that authenticated the user?

Question

I have a customized LoginController with two functions:

loginCustomer that runs Auth::guard('customer')->attempt(...);

loginEmployee that runs Auth::guard('employee')->attempt(...);

I have customized two guards in config.auth that points to my two Models (Customer and Employee) and protect the routes of backoffice and frontend.

Now in my customized LogoutController i want to run Auth::logout() but it doesn't work because i think it uses the default guard.

It only works if i specify Auth::guard('customer')->logout() or Auth::guard('employee')->logout(), depending the guard that was used to login.

Is there any way to get the guard used to authenticate the user so i can use only Auth::guard($guard)->logout?

Answer 1

You can use shouldUse method:

After the call of this method you can logout user via guard you was previously set by shouldUse method.

In your case:

if( Auth::guard('customer')->attempt(...) ){
    Auth::shouldUse('customer');
}


if( Auth::guard('employee')->attempt(...) ){
    Auth::shouldUse('employee');
}

After this you can use Auth::logout and previously choosen guard (via shouldUse) will be used:

// just use Auth::logout without Auth::guard(GUARDNAME)->logout()
Auth::logout();

Short documentation about this method: https://laravel.com/api/5.4/Illuminate/Auth/AuthManager.html#method_shouldUse

Answer 2

This might not be the perfect solution, but it works. Basically, just go through all the guards and check if the user is authenticated by that guard. If he is - log him out. Be aware that this will log him out of all the guards he is logged in to.

This code would go to your logout controller:

  $guards = array_keys(config('auth.guards'));
  foreach ($guards as $guard) {
    if(Auth::guard($guard)->check()) Auth::guard($guard)->logout();
  }