I have this Laravel Query Builder snippet that is working fine:
$records = DB::table('users')
->select(
DB::raw('users.*, activations.id AS activation,
(SELECT roles.name FROM roles
INNER JOIN role_users
ON roles.id = role_users.role_id
WHERE users.id = role_users.user_id LIMIT 1)
AS role')
)
->leftJoin('activations', 'users.id', '=', 'activations.user_id')
->where('users.id', '<>', 1)
->orderBy('last_name')
->orderBy('first_name')
->paginate(10);
Is there a way to avoid use of raw queries and get the same result? In other words, how can I write this in a more "query-builder" style? Can I also translate this into an Eloquent query?
Thanks
You can used selectSub
method for your query.
(1) First create the role query
$role = DB::table('roles')
->select('roles.name')
->join('roles_users', 'roles.id', '=', 'role_users.role_id')
->whereRaw('users.id = role_users.user_id')
->take(1);
(2) Second added the $role
sub query as role
DB::table('users')
->select('users.*', 'activations.id AS activation')
->selectSub($role, 'role') // Role Sub Query As role
->leftJoin('activations', 'users.id', '=', 'activations.user_id')
->where('users.id', '<>', 1)
->orderBy('last_name')
->orderBy('first_name')
->paginate(10);
Output SQL Syntax
"select `users`.*, `activations`.`id` as `activation`,
(select `roles`.`name` from `roles` inner join `roles_users` on `roles`.`id` = `role_users`.`role_id`
where users.id = role_users.user_id limit 1) as `role`
from `users`
left join `activations` on `users`.`id` = `activations`.`user_id`
where `users`.`id` <> ?
order by `last_name` asc, `first_name` asc
limit 10 offset 0"
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