Laravel blade "old input or default variable"?

Question

I want to show the old input in input value. If there isn't old input, than show other variable:

value="{{ old('salary_' . $employee->id) or 'Default' }}" 

But when there is no old input, it gives me 1 instead of the default value!

I think the problem has something to do with the concatenation, but I don't know how to fix it!?

Answer 1

or is a comparison operator in PHP, so your code is evaluating to true, or 1. What you want is a ternary if statement.

As mentioned, or can be used in blade as shorthand for a ternary if statement.

But you can (and should) just pass the default value as the second argument to the function, like so:

value="{{ old('salary_' . $employee->id, 'Default') }}" 

Answer 2

You can use the code (for PHP 7):

{{ old('field_name') ?? $model->field_name ?? 'default' }} 

For checkbox checked attribute use the code (if default value is false):

{{ (old() ? old('field_name', false) : $model->field_name ?? false) ? 'checked' : '' }} 

Construction {{ $something or 'default'}} works only for variables