Laravel Blade @yield and escaping

Question

In Laravel 5 I have a master template containing:

<title>@yield('title') | Site Name</title>

And in my view I have:

@extends('master')

@section('title', $client->name)

...

The problem is, the @yield does not escape the data passed to it. So far, the only solution I've found is to manually escape the data like so:

@section('title', e($client->name))

Is this the best method? It means I have to manually escape data on every view that I use a variable. I don't see a way to escape the @yield directive from the master template - using {{ }} or e() around the @yield doesn't work.

Answer 1

Why not do the following:

@section('title') {{$client->name}} @endsection

This is at least then consistent with escaping data in the rest of your views. The way you have it, you may be very likely to miss an e(). With the above, you will be able to see immediately when you render the view if you have not escaped.

UPDATE

What about using the raw PHP:

<title> <?php echo e($__env->yieldContent('title')); ?> | Site Name</title>

This is what the blade template engine replaces the @yield with, but I've add the escape helper.

This should mean you don't need to escape @section. I think this will work, haven't tried it.