So I Have two collections, sales
and costs
.
Now I need them to combine into one collection for my foreach
condition (I'm not sure if I can use two collections in one foreach
)
RAW Queries:
//Raw MySQL Queries for Sales
$total_sales = DB::raw('SUM(receipts.total) as totalSales');
$year_receipt_created = DB::raw('YEAR(receipts.created_at) as year');
//Raw MyQSL Queries for Cost of Goods Sold
$total_cost = DB::raw('(SUM(qty * cost)) as totalCost');
$year_sold = DB::raw('YEAR(created_at) as year');
Here's my query
for these two collections
:
$sales = DB::table('receipts')
->where('status', 'served')
->where('mode', 'restaurant')
->select($total_sales, $year_receipt_created)
->groupBy('year')
->get();
$costs = DB::table('orders')
->where('status', 'served')
->select($total_cost, $year_sold)
->groupBy('year')
->get();
Things I've tried testing: Converting the collections into array and tried merging them but I seem to have problems.
I reverted it because I don't know if it's the best way or not. Please let me know what's the best way.
UPDATE: Here's the output for those two queries, hope it helps:
Sales
{
totalSales: "960.00",
year: 2017
}
Costs
{
totalCost: "792.00",
year: 2017
}
What I tried: (It says it cannot find totalCost)
//Combining TWO collections into ONE Array
$gross_profit = array();
foreach (array_merge($sales, $costs) as $data)
{
$keys = array('total_sales', 'total_cost', '$year');
$values = array($data->totalSales, $data->totalCost, $data->year);
$gross_profit[$data] = array_combine($keys, $values);
}
**SOLVED: ** I used collection merge
(didn't knew there was such a thing)
The syntax I used is, $result = $sales->merge($costs)
.
Here's the result:
{
totalSales: "960.00",
year: 2017
},
{
totalCost: "792.00",
year: 2017
}
Answered by: Sagar Gautam
Use collection merge()
function like
$result = $sales->merge($costs);
You can see docs https://laravel.com/docs/5.4/collections#method-merge
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