If you need to add multiple elements to a mutable list, you can use the addAll() function. That's all about adding elements to a list in Kotlin.
To add a single element to a list or a set, use the add() function. The specified object is appended to the end of the collection. addAll() adds every element of the argument object to a list or a set. The argument can be an Iterable , a Sequence , or an Array .
Unlike many languages, Kotlin distinguishes between mutable and immutable collections (lists, sets, maps, etc). Precise control over exactly when collections can be edited is useful for eliminating bugs, and for designing good APIs.
https://kotlinlang.org/docs/reference/collections.html
You'll need to use a MutableList
list.
class TempClass {
var myList: MutableList<Int> = mutableListOf<Int>()
fun doSomething() {
// myList = ArrayList<Int>() // initializer is redundant
myList.add(10)
myList.remove(10)
}
}
MutableList<Int> = arrayListOf()
should also work.
Immutable variable with immutable (read only) list:
val users: List<User> = listOf( User("Tom", 32), User("John", 64) )
Immutable variable with mutable list:
val users: MutableList<User> = mutableListOf( User("Tom", 32), User("John", 64) )
or without initial value - empty list and without explicit variable type:
val users = mutableListOf<User>()
//or
val users = ArrayList<User>()
users.add(anohterUser)
or users += anotherUser
(under the hood it's users.add(anohterUser)
)Mutable variable with immutable list:
var users: List<User> = listOf( User("Tom", 32), User("John", 64) )
or without initial value - empty list and without explicit variable type:
var users = emptyList<User>()
users += anotherUser
- *it creates new ArrayList and assigns it to users
Mutable variable with mutable list:
var users: MutableList<User> = mutableListOf( User("Tom", 32), User("John", 64) )
or without initial value - empty list and without explicit variable type:
var users = emptyList<User>().toMutableList()
//or
var users = ArrayList<User>()
users.add(anohterUser)
users += anotherUser
Error: Kotlin: Assignment operators ambiguity:
public operator fun Collection.plus(element: String): List defined in kotlin.collections
@InlineOnly public inline operator fun MutableCollection.plusAssign(element: String): Unit defined in kotlin.collections
see also:
https://kotlinlang.org/docs/reference/collections.html
Agree with all above answers of using MutableList but you can also add/remove from List and get a new list as below.
val newListWithElement = existingList + listOf(element)
val newListMinusElement = existingList - listOf(element)
Or
val newListWithElement = existingList.plus(element)
val newListMinusElement = existingList.minus(element)
Apparently, the default List of Kotlin is immutable. To have a List that could change, one should use MutableList as below
class TempClass {
var myList: MutableList<Int>? = null
fun doSomething() {
myList = ArrayList<Int>()
myList!!.add(10)
myList!!.remove(10)
}
}
Updated Nonetheless, it is not recommended to use MutableList unless for a list that you really want to change. Refers to https://hackernoon.com/read-only-collection-in-kotlin-leads-to-better-coding-40cdfa4c6359 for how Read-only collection provides better coding.
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