JS regex: replace all digits in string

Question

I need to replace all digits.

My function only replaces the first digit.

var s = "04.07.2012"; alert(s.replace(new RegExp("[0-9]"), "X")); // returns "X4.07.2012"                                             // should be XX.XX.XXXX" 

Answer 1

You need to add the "global" flag to your regex:

s.replace(new RegExp("[0-9]", "g"), "X") 

or, perhaps prettier, using the built-in literal regexp syntax:

.replace(/[0-9]/g, "X") 

Answer 2

Use

s.replace(/\d/g, "X") 

which will replace all occurrences. The g means global match and thus will not stop matching after the first occurrence.

Or to stay with your RegExp constructor:

s.replace(new RegExp("\\d", "g"), "X")