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jQuery's function $(function())’s execute order when the $(function()) called more one times

Code like this:

$(window.document).ready(function () {
    window.alert('alert 1');
});

$(function () {
    window.alert('alert 2');
});

$(function () {
   window.alert('alert 3');
});
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Demo2</title>
    <script src="jquery-3.1.1.js"></script>
    <script src="demo2.js"></script>
</head>
<body>

</body>
</html>

when i execute the above code, the page' alert order sometimes is: alert 1, alert 2, alert 3, and sometimes is: alert 1, alert 3, alert 2. could anyone tell my why?

like image 791
zhuochangjing Avatar asked Oct 29 '22 19:10

zhuochangjing


1 Answers

At lines 3930 through 3947 jQuery version 3.1.1 handles .ready() being called after document has already loaded. At line 3938 jQuery.ready is called inside of setTimeout without a duration set with attached comment

// Handle it asynchronously to allow scripts the opportunity to delay ready

which would explain how window.alert('alert 3') could potentially be called before window.alert('alert 2')


// Catch cases where $(document).ready() is called
// after the browser event has already occurred.
// Support: IE <=9 - 10 only
// Older IE sometimes signals "interactive" too soon
if ( document.readyState === "complete" ||
    ( document.readyState !== "loading" && !document.documentElement.doScroll ) ) {

    // Handle it asynchronously to allow scripts the opportunity to delay ready
    window.setTimeout( jQuery.ready ); // Line 3938

} else {

    // Use the handy event callback
    document.addEventListener( "DOMContentLoaded", completed );

    // A fallback to window.onload, that will always work
    window.addEventListener( "load", completed );
}

The following stacksnippet should reproduce result described by OP

<!DOCTYPE html>
<html lang="en">

<head>
  <meta charset="UTF-8">
  <title>Demo2</title>
  <script src="https://code.jquery.com/jquery-3.1.1.js"></script>
  <script>
    $(window.document).ready(function() {
      window.alert('alert 1');
    });

    $(function() {
      window.alert('alert 2');
    });

    $(function() {
      window.alert('alert 3');
    });
  </script>
</head>

<body>

</body>

</html>

See also completed function at Line 3924

// The ready event handler and self cleanup method
function completed() {
    document.removeEventListener( "DOMContentLoaded", completed );
    window.removeEventListener( "load", completed );
    jQuery.ready();
}

See plnkr http://plnkr.co/edit/C0leBhYJq8CMh7WqndzH?p=preview at version 1


Edit, Updated

To ensure the order of execution of functions at .ready() you can return a promise from the function calls, use .then() inside single .ready() call to call functions defined globally or previously within .ready() handler.

<!DOCTYPE html>
<html lang="en">

<head>
  <meta charset="UTF-8">
  <title>Demo2</title>
  <script src="https://code.jquery.com/jquery-3.1.1.js"></script>
  <script>
    function ready1(wait, index) {
      // do stuff
      return new Promise(resolve => {
          setTimeout(() => {
            window.alert('alert ' + index);
            resolve(index)
          }, wait)
        })
        .then((i) => console.log(i))
    }

    function ready2(wait, index) {
      // do stuff
      return new Promise(resolve => {
          setTimeout(() => {
            window.alert('alert ' + index);
            resolve(index)
          }, wait)
        })
        .then((i) => console.log(i))
    }

    function ready3(wait, index) {
      // do stuff
      return new Promise(resolve => {
          setTimeout(() => {
            window.alert('alert' + index);
            resolve(index)
          }, wait)
        })
        .then((i) => console.log(i))
    }
    $().ready(function() {
      ready1(3000, 0) 
      .then(function() {
        return ready2(1500, 1) 
      })
      .then(function() {
        return ready3(750, 2) 
      });
    })
  </script>
</head>

</html>
like image 118
guest271314 Avatar answered Nov 12 '22 17:11

guest271314